Please give me answer

Simplify: B + (BC)’
1.0

2.1

3.C + B’
4.B + C’

Following is the solution.

B + (BC)'
B + B' + C'
(B + B') + C'
1 + C' {∵ X + X’ = 1}
1 {∵ 1 + X = 1}

use distrubutive law like a+bc = (a+b)(A+C)