The Boolean expression \displaystyle\overline{{{\left({a}+\overline{{b}}+{c}+\overline{{d}}\right)}+{\left({b}+\overline{{c}}\right)}}} simplifies to

(a) \displaystyle{1}

(b) \displaystyle\overline{{{a}.{b}}}

(c) \displaystyle{a}.{b}

(d) \displaystyle{0}

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Ans is D b+b’=1and 1+anything will always be 1 but complement of that will be 0

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Option D

b+b’ = 1

c+c’ = 1

(1+ a + d’) = 1

complement of 1 = 0

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a’.(b’)’.c’.(d’)’.(b’.(c’)’)

=(a’bc’d)(b’.c)

=0

bcoz b.b’=0

Vinni
#7
D will be the right answer…

Alok
#8
Answer. D

As we know x+x’=1

So a+b+b’+c+c’+d’=1+a+d’=1 (1+x=1)

1’=0

Option 1 is correct

Because 1+any is 1

Answer D

Because I got that ans by solving