The Boolean expression \displaystyle\overline{{{\left({a}+\overline{{b}}+{c}+\overline{{d}}\right)}+{\left({b}+\overline{{c}}\right)}}} simplifies to
(a) \displaystyle{1}
(b) \displaystyle\overline{{{a}.{b}}}
(c) \displaystyle{a}.{b}
(d) \displaystyle{0}
Ans is D b+b’=1and 1+anything will always be 1 but complement of that will be 0
Option D is correct ans
D part is correct i.e 0
Option D
b+b’ = 1
c+c’ = 1
(1+ a + d’) = 1
complement of 1 = 0
a’.(b’)’.c’.(d’)’.(b’.(c’)’)
=(a’bc’d)(b’.c)
=0
bcoz b.b’=0
D will be the right answer…
Answer. D
As we know x+x’=1
So a+b+b’+c+c’+d’=1+a+d’=1 (1+x=1)
1’=0
Option 1 is correct
Because 1+any is 1
Answer D
Because I got that ans by solving