Wattmeter problem Q.no-78

answer is 8000 watt.
P = VI
=30×600
=18000 watt.
scale is for 4500 watt.
so, when pointer will show 1 watt, actual reading
will be 18000/4500=4watt i.e 4 times of meter reading
similarly, if pointer shows 2000 watt, then actual rading
will be 4 times of 2000 i.e 8000 watts.

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