Digital Electronics Practice Problem-6


#1

The Boolean expression \displaystyle\overline{{{\left({a}+\overline{{b}}+{c}+\overline{{d}}\right)}+{\left({b}+\overline{{c}}\right)}}} simplifies to

(a) \displaystyle{1}
(b) \displaystyle\overline{{{a}.{b}}}
(c) \displaystyle{a}.{b}
(d) \displaystyle{0}


#2

Ans is D b+b’=1and 1+anything will always be 1 but complement of that will be 0


#3

Option D is correct ans


#4

D part is correct i.e 0


#5

Option D

b+b’ = 1
c+c’ = 1
(1+ a + d’) = 1
complement of 1 = 0